To solve a two step equation with a fraction like the following:

(^{3}⁄_{10})*x* + 5 = 11 you need to undo what has been done to the *x* using inverse operations. Think of it as going backwards while doing PEMDAS, or Order of Operations. So if I were to go backwards I would undo the addition first by completing the inverse operation, subtraction. So I would subtract 5 from both sides to get:

(^{3}⁄_{10})*x* = 6

O.k. so now we have ^{3}⁄_{10} being multiplied by *x* so to undo that we have to divide *x* by the reciprocal, which is ^{10}⁄_{3}. To get the reciprocal just remember to flip the numerator and denominator. O.k., so after doing that we have:

*x* = ^{60}⁄_{3}

Our last step is to simplify ^{60}⁄_{3} to just 20, so:

*x* = 20!

And it is as simple as that!

© Copyright 2016 I will solve that! All rights reserved. http://www.iwillsolvethat.com